Question

拋物線y=x²+1關(guān)于原點(diǎn)對(duì)稱的拋物線的解析式為（　�。�

A．y=x²-1

B．y=-x²-1

C．y=-x²+1

D．y=-（x+1）²

Answer 1

分析：根據(jù)關(guān)于原點(diǎn)對(duì)稱的點(diǎn)的坐標(biāo)特點(diǎn)進(jìn)行解答即可．

解答：解：∵關(guān)于原點(diǎn)對(duì)稱的點(diǎn)的橫縱坐標(biāo)互為相反數(shù)，
∴拋物線y=x²+1關(guān)于原點(diǎn)對(duì)稱的拋物線的解析式為：-y=（-x）²+1，即y=-x²-1．
故選B．

點(diǎn)評(píng)：本題考查的是二次函數(shù)的圖象與幾何變換，熟知關(guān)于原點(diǎn)對(duì)稱的點(diǎn)的坐標(biāo)特點(diǎn)是解答此題的關(guān)鍵．