三角形內(nèi)角平分線性質(zhì)定理:三角形的內(nèi)角平分線分對(duì)邊所得的兩條線段和這個(gè)角的兩邊對(duì)應(yīng)成比例。
已知:如圖,△ABC中,AD是角平分線.
求證:(1)BD/DC=AB/AC
(2)若AD是三角形ABC外角的平分線,交BC延長(zhǎng)線于點(diǎn)D,是否還有以上結(jié)論?
(1) 過(guò)C作CE∥DA,交BA的延長(zhǎng)線于E.∵CE∥DA∴∠1=∠E,∠2=∠3,∠1=∠2∴∠E=∠3∴AE=AC∵CE∥DA∴BD/DC=BA/AE又∵AE=AC∴BD/DC=AB/AC(2)在BA延長(zhǎng)線上取點(diǎn)C',使AC'=AC,過(guò)C'作C'D'//CD交DA延長(zhǎng)線于點(diǎn)D',連接C'D.∵C'D'//CD,A是BA與DD'的交點(diǎn)∴△ABD∽△AC'D'∴BD/C'D'=AB/AC'∵C'D'//CD∴∠C'D'A=∠ADB∵AD是三角形ABC外角的平分線∴∠C'AD=∠CAD∵AC'=AC,AD是公共邊∴△C'AD≌△CAD∴∠C'DA=∠ADB,C'D=CD∴∠C'DA=∠C'D'A∴C'D'=C'D=CD∴BD/DC=BD/C'D'=AB/AC'=AB/AC