Question

u-2v

u+2v

-

2

u2-4v2

．

Answer 1

分析：首先通分，將原式通分為

(u-2v)2

(u+2v)(u-2v)

-

2

(u+2v)(u-2v)

，然后利用同分母的分式相加減的運(yùn)算法則求解即可求得答案．

解答：解：

u-2v

u+2v

-

2

u2-4v2

=

(u-2v)2

(u+2v)(u-2v)

-

2

(u+2v)(u-2v)

=

u2-4uv+v2-2

(u+2v)(u-2v)

．

點(diǎn)評：此題考查了異分母分式的加減運(yùn)算法則．注意先通分，再利用同分母的分式相加減的運(yùn)算法則求解即可，注意運(yùn)算結(jié)果需化為最簡．