解:(1)3x
2+2x-5x
2+3x
=(3-5)x
2+(2+3)x
=-2x
2+5x;
(2)4(m
2+n)+2(n-2m
2)
=4m
2+4n+2n-4m
2
=6n;
(3)5ab
2-[a
2b+2(a
2b-3ab
2)]
=5ab
2-a
2b-2(a
2b-3ab
2)
=5ab
2-a
2b-2a
2b+6ab
2
=11ab
2-3a
2b;
(4)3A-2B
=3(x
2-3x-6)-2(2x
2-4x+6)
=3x
2-9x-18-4x
2+8x-12
=-x
2-x-30
當(dāng)x=-1時(shí):原式=-(-1)
2-(-1)-30=-1+1-30=-30;
(5)∵|x+1|≥0

≥0且|x+1|+

=0
∴x+1=0 y-

=0
解得:x=-1 y=

代入數(shù)值轉(zhuǎn)換器得:[(-1)
2+2×

+1]÷2=

分析:(1)合并同類(lèi)項(xiàng)即可;
(2)去括號(hào)合并同類(lèi)項(xiàng)即可;
(3)去括號(hào)合并同類(lèi)項(xiàng)即可;
(4)將A與B代入到3A-2B中化簡(jiǎn)后求值即可;
(5)利用原式求得x、y值后代入數(shù)值轉(zhuǎn)換器求值即可;
點(diǎn)評(píng):本題考查了整式的加減及代數(shù)式求值的問(wèn)題,解題的關(guān)鍵是正確的運(yùn)用整式的加減的有關(guān)法則進(jìn)行運(yùn)算.