解:(1)(2x+1)(-2x+1),
=1
2-(2x)
2,
=1-4x
2;
(2)(2a-

b
2)
2,
=(2a)
2-2×2a×

b
2+

,
=4a
2-2ab
2+

;
(3)(3x+1)
2(3x-1)
2,
=[(3x+1)(3x-1)]
2,
=(9x
2-1)
2,
=81x
4-18x
2+1;
(4)(x+1)(x
2+1)(x
4+1)(x-1),
=(x+1)(x-1)(x
2+1)(x
4+1),
=(x
2-1)(x
2+1)(x
4+1),
=(x
4-1)(x
4+1),
=x
8-1.
分析:(1)根據(jù)平方差公式,找準a、b對應的數(shù),再解答;
(2)根據(jù)完全平方公式,計算;
(3)和(4)可根據(jù)平方差公式,計算解答.
點評:本題考查了平方差公式和完全平方公式,熟練掌握這些公式是解題的關鍵.公式:(a+b)(a-b)=a
2-b
2,(a±b)
2=a
2±2ab+b
2.