Question

x^m+n÷x^n-2的結(jié)果是

1. A.
   x^m+n-2
2. B.
   x^m+2n-2
3. C.
   x^m+2
4. D.
   x^n-2

Answer 1

C
分析：根據(jù)同底數(shù)冪相除，底數(shù)不變指數(shù)相減進(jìn)行計(jì)算即可得解．
解答：x^m+n÷x^n-2
=x^m+n-n+2
=xⁿ⁺²．
故選C．
點(diǎn)評(píng)：本題考查了同底數(shù)冪的除法，熟記運(yùn)算性質(zhì)是解題的關(guān)鍵．