Question

計(jì)算：

x+2y

1-x2

+

y-1

x2-1

-

y

1-x2

．

Answer 1

分析：先通分，然后進(jìn)行同分母分式加減運(yùn)算，最后要注意將結(jié)果化為最簡(jiǎn)分式．

解答：解：原式=

x+2y

1-x2

-

y-1

1-x2

-

y

1-x2

=

x+2y-y+1-y

1-x2

=

x+1

1-x2

=

1

1-x

．

點(diǎn)評(píng)：本題主要考查分式的加減法運(yùn)算，基礎(chǔ)題，比較簡(jiǎn)單．