（7分）根據(jù)圖示回答下列問題：

（1）寫出G的結(jié)構(gòu)簡式：                              ；
（2）反應(yīng)③的化學方程式是                                         ，
反應(yīng)④的化學方程式是                                             ；
（3）寫出②、⑤的反應(yīng)類型：②                、⑤                   。
（1）HOOC（CH2）4COOH（1分）
（2）（2分）
（2分）
（3）消去反應(yīng)，    縮聚反應(yīng)       （每空1分）解析:
本題屬于有機合成題。根據(jù)F和G的反應(yīng)得到的生成物結(jié)構(gòu)簡式可判斷，反應(yīng)⑤是縮聚反應(yīng)。因此F是乙二醇，G是1，6－己二酸，結(jié)構(gòu)簡式為HOOC（CH2）4COOH。氯代烴水解可生成醇，所以C是1，2－二氯乙烷，因此A是乙烯，B是氯氣，通過加成反應(yīng)得到C。根據(jù)D的分子式可判斷，C通過消去反應(yīng)生成D，即D是氯乙烯，結(jié)構(gòu)簡式為CH2＝CHCl。氯乙烯甲聚即得到高分子化合物E，結(jié)構(gòu)簡式為。
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