精英家教網 > 高中地理 > 題目詳情

【題目】在不同高度同時釋放兩個鉛球不計空氣阻力,則在均未落地前,兩者

在任一時刻具有相同的加速度、位移和速度

落地的時間間隔取決于兩鉛球釋放時的高度

在第1 s內、第2 s內、第3 s內位移之比都為149

兩鉛球的距離和速度差都越來越大

A只有①②正確 B只有①②③正確

C只有①③④正確 D①②③④都正確

【答案】A

【解析】兩個鉛球都做自由落體運動,所以加速度都等于重力加速度,即加速度相等;由于同時釋放,所以運動時間相同;根據公式h=gt2可得發(fā)生的位移相等,任意時刻的速度v=gt相等,正確;兩鉛球落地的時間間隔為Δt=,即取決于兩鉛球下落的高度,正確;在第1 s內、第2 s內、第3 s內位移之比都為135,錯誤;因為是同時釋放的,所以兩鉛球下落過程中相同時間內的位移和速度都相等,故距離差是一個定值,即釋放前的高度差,錯誤。顯然只有選項A正確。

練習冊系列答案
相關習題

科目:高中地理 來源: 題型:

【題目】短文改錯

A little kid fell into the lake while she was playing with her little friends. They were too frightening to know what to do next. Unfortunately, a pretty lady and a man passed by and saw the drowning girl. The man immediate dived into the water and took the girl to the bank and at a same time. The lady called the ambulance on time. Before the ambulance came, the lady, who proved to be a nurse, performing first aid to the kid. A few of minutes later, the kid sent to the nearest hospital and finally saved. The story is a good example where first aid can make a lot of differences. From it, we know it is necessary to know basic first aid skills so that we can be better preparing for an emergency.

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】、短文改錯

假定英語課上老師要求同桌之間交換修改作文,請你修改你同桌寫的以下作文。文中共有10處語言錯誤,每句中最多有兩處。錯誤涉及一個單詞的增加、刪除或修改。

增加:在缺詞處加一個漏詞符號(∧),并在其下面寫出該加的詞。

刪除:把多余的詞用斜線(\)劃掉。

修改:在錯的詞下劃一橫線,并在該詞下面寫出修改后的詞。

注意:

1. 每處錯誤及其修改均僅限一詞;

2. 只允許修改10處,多者(從第11處起)不計分。

Last Sunday, I sat at my favorite table in a restaurant and wait for the food I had ordered to arrive. Suddenly I found that Lin Ling, one of my classmate, worked like a waitress there. Honest speaking, it was great surprise for me to find her working there. As far as I know, she’s from a richer family. What was it that made her to work there? I walked up to her and asked her the reason. When asking, she said, I just want to earn some pocket money so that we can help some children in poor areas go back to school. How a good girl! I should learn from her.

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】短文改錯

假定英語課上老師要求同桌之間交換修改作文,請你修改你同桌寫的以下作文。文中共有10處語言錯誤,每句中最多有兩處。錯誤涉及一個單詞的增加、刪除或修改。

增加:在缺詞處加一個漏詞符號(∧),并在其下面寫出該加的詞。

刪除:把多余的詞用斜線(\)劃掉。

修改:在錯的詞下劃一橫線,并在該詞下面寫出修改后的詞。

注意:

1. 每處錯誤及其修改均僅限一詞;

2. 只允許修改10處,多者(從第11處起)不計分。

In the past, I always think my little brother was very unpleasant, because he used to ask me some questions every time he did his homeworks. I felt as if I had been the smartest person in the world every time he accepted my explanations. Answered one of his questions, I often liked to say that he was too stupidly to solve such simple questions.

Last week both us received our report cards from our school. Unexpectedly, I got Cs, when he got straight As. To make things bad, all the day my brother screamed what foolish it was of me not to ask questions! I just sighed and had to admit that she was right. I have never made a fun of him since then.

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】一種半導體材料稱為“霍爾材料”,用它制成的元件稱為“霍爾元件”,這種材料有可定向移動的電荷,稱為“載流子”,每個載流子的電荷量大小為1個元電荷量,即q=16×10-19 C,霍爾元件在自動檢測、控制領域得到廣泛應用,如錄像機中用來測量錄像磁鼓的轉速、電梯中用來檢測電梯門是否關閉以及自動控制升降電動機的電源的通斷等。在一次實驗中,一塊霍爾材料制成的薄片寬AB=10×10-2m、長BC=40×10-2m、厚h=1×10-3m,水平放置在豎直方向上的磁感應強度B=15 T的勻強磁場中,BC方向通有I=30 A的電流,如圖所示,沿寬度產生10×10-5 V的橫向電壓

1假定載流子是電子,A、B兩端中哪端電勢較高?

2薄板中形成電流I的載流子定向運動的速率多大?

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】一臺發(fā)電機最大輸出功率為4 000 kW,電壓為4 000 V,經變壓器T1壓后向遠方輸電輸電線路總電阻R=1 。到目的地經變壓器T2降壓,負載為多個正常發(fā)光的燈泡220 V,60 W。若在輸電線路上消耗的功率為發(fā)電機輸出功率的10%,變壓器T1和T2的耗損可忽略,發(fā)電機處于滿負荷工作狀態(tài),則

AT1原、副線圈電流分別為103 A和20 A

BT2原、副線圈電壓分別為18×105 V和220 V

CT1和T2的變壓比分別為150和401

D有6×104盞燈泡220 V,60 W正常發(fā)光

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】如圖所示是使用光電管的原理圖,當頻率為ν的可見光照射到陰極K上時,電流表中有電流通過。

1當變阻器的滑動端P向________滑動時填“左”或”右”,通過電流表的電流將會增大。

2當電流表電流剛減小到零時,電壓表的讀數(shù)為U,則光電子的最大初動能為________已知電子電荷量為e。

3如果不改變入射光的頻率,而增加入射光的強度,則光電子的最大初動能將________填“增加”“減小”或“不變”。

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】聽下面一段對話,完成五道小題,每小題填寫一個詞。這段對話你將聽兩遍。

查看答案和解析>>

科目:高中地理 來源: 題型:

【題目】如圖所示,A、B是兩塊平行金屬極板,充電后與電源斷開。A板帶正電,B板帶負電并與地連接,有一帶電微粒懸浮在兩板間P點處靜止不動。現(xiàn)將B板上移到虛線處,則下列說法正確的是

A.帶電微粒的電性為正

B.平行板電容器電容增大

C.極板間P點的電勢升高

D.帶電微粒的電勢能增大

查看答案和解析>>

同步練習冊答案