設(shè)數(shù)列{an}的前n項和為Sn,則下列說法錯誤的是________.
①若{an}是等差數(shù)列,則{3an+1-2an}是等差數(shù)列;
②若{an}是等差數(shù)列,則{|an|}是等差數(shù)列;
③若{an}是公比為q的等比數(shù)列,則{an+1-an}也是等比數(shù)列且公比為q;
④若{an}是公比為q的等比數(shù)列,則Sk,S2k-Sk,S3k-S2k(k為常數(shù)且k∈N)也是等比數(shù)列且公比為qk.
②③④
分析:①設(shè)數(shù)列{an}的公差為d,利用等差數(shù)列的定義進行判斷;②③④列舉反例,可得結(jié)論:②{an}是以-1為首項,2為公差的等差數(shù)列;③{an}是公比為1的等比數(shù)列;④{an}是公比為-1的等比數(shù)列.
解答:①設(shè)數(shù)列{an}的公差為d,
∵{an}是等差數(shù)列,∴an+1-an=d,∴an-an-1=d
∴(3an+1-2an)-(3an-2an-1)=3(an+1-an)-2(an-an-1)=3d-2d=d
∴{3an+1-2an}是等差數(shù)列,故①正確;
②若{an}是以-1為首項,2為公差的等差數(shù)列,{|an|}不是等差數(shù)列,故②錯誤;
③若{an}是公比為1的等比數(shù)列,則{an+1-an}不是等比數(shù)列,故③錯誤;
④若{an}是公比為-1的等比數(shù)列,則Sk,S2k-Sk,S3k-S2k(k為常數(shù)且k∈N)不一定是等比數(shù)列,故④錯誤
故答案為:②③④
點評:本題考查命題的真假判斷,考查數(shù)列的性質(zhì),正確命題要嚴格注明,錯誤命題列舉反例即可.