已知等差數(shù)列{}中共有18項,其中奇數(shù)項之和為11,偶數(shù)項之和為29,則其公差為(     )

A.4B.3C.2D.1

C

解析考點:等差數(shù)列的性質(zhì).
分析:由題意可得奇數(shù)項有9項,偶數(shù)項有9項,設(shè)公差為d,則由 9d="29-11" 即可求得公差d的值.
解:由題意可得奇數(shù)項有9項,偶數(shù)項有9項,設(shè)公差為d,則 9d=29-11=18,
∴d=2,
故選C.

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