試題分析:(1)本題有兩個化簡方向,一是展開,利用同角三角函數(shù)關(guān)系求角,即
,結(jié)合
解得
,二是利用角的關(guān)系,即
(2)研究函數(shù)性質(zhì),首先化為一元函數(shù),即利用二倍角公式化簡得:
,因?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824044345662565.png" style="vertical-align:middle;" />,所以值域?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824044345506510.png" style="vertical-align:middle;" />.
試題解析:(1)因?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824044345693658.png" style="vertical-align:middle;" />,且
,所以
,
.
因?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/201408240443457401969.png" style="vertical-align:middle;" />
.所以
. 6
(2)由(1)可得
. 所以
,
. 因?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824044345662565.png" style="vertical-align:middle;" />,所以,當(dāng)
時,
取最大值
;當(dāng)
時,
取最小值
.
所以函數(shù)
的值域?yàn)?img src="http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824044345506510.png" style="vertical-align:middle;" />. 14分