分析:本題是一個(gè)分段函數(shù),當(dāng)x≤1時(shí)其為一指數(shù)函數(shù),當(dāng)x<1時(shí),其為一對(duì)數(shù)函數(shù),故可分別根據(jù)相關(guān)函數(shù)的性質(zhì)研究其單調(diào)性與相應(yīng)區(qū)間上函數(shù)圖象變化的對(duì)應(yīng),由此即可選出正確選項(xiàng).
解答:解:由函數(shù)
f(x)=知,
當(dāng)x≤1時(shí)其為一指數(shù)函數(shù),由于其底數(shù)為2,故在區(qū)間(-∞,1)上是增函數(shù),且過(0,1)點(diǎn),右端點(diǎn)坐標(biāo)為(1,2)
當(dāng)x>1時(shí),其為一對(duì)數(shù)函數(shù),由于其底數(shù)為
,故在區(qū)間(1,+∞)上是減函數(shù),且左端點(diǎn)坐標(biāo)為(1,0)
觀察四個(gè)選項(xiàng),A、B中圖象不過(0,1)點(diǎn),D中圖象不過(1,0),B中圖象變化符合函數(shù)的性質(zhì)
故選B
點(diǎn)評(píng):本題考點(diǎn)是指數(shù)函數(shù)的圖象與性質(zhì),考查函數(shù)圖象的變化與函數(shù)性質(zhì)的對(duì)應(yīng),指數(shù)函數(shù)的底數(shù)大于1,其單調(diào)性為增,圖象是上升的;底數(shù)大于0小于1時(shí)其單調(diào)性為減,圖象是下降的,圖象恒過;對(duì)數(shù)數(shù)函數(shù)的底數(shù)大于1,其單調(diào)性為增,圖象是上升的;底數(shù)大于0小于1時(shí)其單調(diào)性為減,圖象是下降的,圖象恒過(1,0);熟練掌握函數(shù)的這些性質(zhì)可以提高解題的速度與準(zhǔn)確性.