題目列表(包括答案和解析)
已知函數(shù)f(x) =2x+1,x∈R.規(guī)定:給定一個實(shí)數(shù)x0,賦值x1= f(x0),若x1≤255,則繼續(xù)賦值x2= f(x1) …,以此類推,若x n-1≤255,則xn= f(xn-1),否則停止賦值,如果得到xn后停止,則稱賦值了n次(n∈N *).已知賦值k次后該過程停止,則x0的取值范圍是
(A)(2k-9 ,2 k-8] (B)(2 k-8 -1, 2k-9-1](C)(28-k -1, 29-k-1] (D)(27-k -1, 28-k-1]
已知函數(shù)f(x) =2x+1,x∈R.規(guī)定:給定一個實(shí)數(shù)x0,賦值x1= f(x0),若x1≤255,則繼續(xù)賦值x2=" f(x1)" …,以此類推,若x n-1≤255,則xn= f(xn-1),否則停止賦值,如果得到xn后停止,則稱賦值了n次(n∈N *).已知賦值k次后該過程停止,則x0的取值范圍是
A.(2k-9 ,2 k-8] | B.(2 k-8 -1, 2k-9-1] | C.(28-k -1, 29-k-1] | D.(27-k -1, 28-k-1] |
已知函數(shù)f(x) =2x+1,x∈R.規(guī)定:給定一個實(shí)數(shù)x0,賦值x1= f(x0),若x1≤255,則繼續(xù)賦值x2= f(x1) …,以此類推,若x n-1≤255,則xn= f(xn-1),否則停止賦值,如果得到xn后停止,則稱賦值了n次(n∈N *).已知賦值k次后該過程停止,則x0的取值范圍是 ( )
(A)(2k-9 ,2 k-8] (B)(2 k-8 -1, 2k-9-1] (C)(28-k -1, 29-k-1] (D)(27-k -1, 28-k-1]
已知函數(shù)f(x) =2x+1,x∈R.規(guī)定:給定一個實(shí)數(shù)x0,賦值x1= f(x0),若x1≤255,則繼續(xù)賦值x2= f(x1) …,以此類推,若x n-1≤255,則xn= f(xn-1),否則停止賦值,如果得到xn后停止,則稱賦值了n次(n∈N *).已知賦值k次后該過程停止,則x0的取值范圍是 ( )
(A)(2k-9 ,2 k-8] (B)(2 k-8 -1, 2k-9-1] (C)(28-k -1, 29-k-1] (D)(27-k -1, 28-k-1]
湖北省互聯(lián)網(wǎng)違法和不良信息舉報平臺 | 網(wǎng)上有害信息舉報專區(qū) | 電信詐騙舉報專區(qū) | 涉歷史虛無主義有害信息舉報專區(qū) | 涉企侵權(quán)舉報專區(qū)
違法和不良信息舉報電話:027-86699610 舉報郵箱:58377363@163.com