8.已知函數(shù)f (x) = 3-2 |x|, g(x) = x2-2x,構(gòu)造函數(shù)y = F(x).定義如下:當(dāng)f (x)≥g (x)時(shí).F(x) = g(x),當(dāng)f (x) < g (x)時(shí).F(x) = f (x).那么F(x) A.有最大值3.最小值-1 B.有最大值3.無最小值 C.有最大值7.無最小值 D.無最大值.也無最小值 查看更多

 

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已知函數(shù)f (x) = 3-2 |x|, g(x) = x2-2x,構(gòu)造函數(shù)y = F(x),定義如下:當(dāng)f (x)≥g (x)時(shí),F(x) = g(x);當(dāng)f (x) < g (x)時(shí),F(x) = f (x),那么F(x)          (         )

   A.有最大值3,最小值-1                  B.有最大值3,無最小值

C.有最大值7,無最小值            D.無最大值,也無最小值

 

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已知函數(shù)f (x) = 3-2 |x|, g(x) = x2-2x,構(gòu)造函數(shù)y = F(x),定義如下:當(dāng)f (x)≥g (x)時(shí),F(x) = g(x);當(dāng)f (x) < g (x)時(shí),F(x) = f (x),那么F(x)          (         )

A.有最大值3,最小值-1 B.有最大值3,無最小值
C.有最大值7,無最小值 D.無最大值,也無最小值

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已知函數(shù)f(x)和g(x)的圖象關(guān)于原點(diǎn)對(duì)稱,且f(x)=x2+2x,

(1)求函數(shù)g(x)的解析式;

(2)解不等式g(x)≥f(x)-|x-1|;

(3)若h(x)=g(x)-λf(x)+1在[-1,1]上是增函數(shù),求實(shí)數(shù)λ的取值范圍.

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已知函數(shù)f(x)=ax2-(2a+1)x+2lnx(a∈R).

(1)若曲線yf(x)在x=1和x=3處的切線互相平行,求a的值;

(2)求f(x)的單調(diào)區(qū)間;

(3)設(shè)g(x)=x2-2x,若對(duì)任意x1∈(0,2],均存在x2∈(0,2],使得f(x1)<g(x2),求a的取值范圍.

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已知函數(shù)f(x)=3-2|x|,g(x)=x2-2x,構(gòu)造函數(shù)F(x),定義如下:當(dāng)f(x)≥g(x)時(shí),F(xiàn)(x)=g(x);當(dāng)f(x)<g(x)時(shí),F(xiàn)(x)=f(x),那么F(x)(  )

A.有最大值3,最小值-1

B.有最大值3,無最小值

C.有最大值7-,無最小值

D.無最大值,也無最小值

 

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