分析:(1)運(yùn)用乘法分配律的逆運(yùn)算簡(jiǎn)算;
(2)把99看作98+1,運(yùn)用乘法分配律簡(jiǎn)算;
(3)把分?jǐn)?shù)和百分?jǐn)?shù)化為小數(shù),運(yùn)用乘法分配律的逆運(yùn)算簡(jiǎn)算;
(4)此題可用分?jǐn)?shù)拆項(xiàng)的方法解答.通過(guò)觀察,每個(gè)分?jǐn)?shù)的分子都是兩個(gè)連續(xù)自然數(shù)的乘積,因此可以把每個(gè)分?jǐn)?shù)拆成兩個(gè)分?jǐn)?shù)相減的形式,然后通過(guò)加減相互抵消,得出結(jié)果.
解答:解:(1)
×18-7×
-
,
=
×(18-7-1),
=
×10,
=6;
(2)99×
,
=(98+1)×
,
=98×
+1×
,
=97+
,
=97
;
(3)
×7.7+3.3×0.8-80%,
=0.8×7.7+3.3×0.8-0.8,
=0.8×(7.7+3.3-1),
=0.8×10,
=8;
(4)
+
+
+
+
+
,
=1-
+
-
+
-
+
-
+
-
+
-
,
=1-
,
=
.
點(diǎn)評(píng):解答四則混合運(yùn)算的題目,要仔細(xì)觀察,抓住特點(diǎn),運(yùn)用所學(xué)知識(shí),進(jìn)行巧妙解答.