64=2×2×2×2×2×2表示成f(64)=6;243=3×3×3×3×3表示成g(243)=5.
試求下列的值:
(1)f(128)=
7
7

(2)f(16)=g
81
81
;
(3)f
(8)
(8)
+g(27)=6;
(4)如果x,y分別表示若干個2的數(shù)的乘積,試證明:f(x?y)=f(x)+f(y).
分析:先看第一種新的運算即“f”的運算意義是什么;再看第二種新的運算即“g”的運算意義是什么,根據(jù)此兩個符號的運算意義,運用到所求的式子,即可得到答案.
解答:解:(1)f(128)=f(27)=7;
(2)f(16)=f(24)=4=g(34)=g(81);
(3)因為6-g(27)=6-g(33)=6-3=3=f(23)=f(8),
所以f(8)+g(27)=6;
(4)令x=2m,y=2n,
則f(x)=m,f(y)
=n.f(x?y)
=f(2m?2n
=f(2m+n
=m+n
=f(x)+f(y).
故答案為:7,81,(8).
點評:解答此題最重要的是,要徹底弄清楚新運算符號的意義,然后再利用新運算方法,來分別計算要求的題目.
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