Question

15．解方程：$\frac{0.2x-0.1}{0.3}$-$\frac{100x+10}{120}$=$\frac{0.02+0.01}{0.04}$-2．

Answer 1

分析 關(guān)鍵分?jǐn)?shù)的基本性質(zhì)把$\frac{0.2x-0.1}{0.3}$、$\frac{100x+10}{120}$、$\frac{0.02+0.01}{0.04}$用進(jìn)行化簡．然后再進(jìn)行解答方程即可．

解答 解：$\frac{0.2x-0.1}{0.3}$-$\frac{100x+10}{120}$=$\frac{0.02+0.01}{0.04}$-2
         $\frac{2x-1}{3}$-$\frac{10x-1}{12}$=$\frac{3}{4}$
        $\frac{8x-4}{12}-\frac{10x-1}{12}$=$\frac{3}{4}$
               $\frac{18x-5}{12}$=$\frac{3}{4}$
               72x-20=36
            72x+20-20=36+20
               72x÷72=56÷72
                     x=$\frac{7}{9}$

點評 本題運用等式的性質(zhì)進(jìn)行解答即可，解答過程中注意等于號要對齊．