解:①[4
-(
+1
×2)]÷2
=[4
-
-3
]÷2
,
=
×
,
=
;
②0.68×
-
×
+
×68%
=0.68×
-
×0.68+
×0.68,
=(
-
+
)×0.68,
=1×0.68,
=0.68;
③[1
+2
×(2
-2.375)]×
÷7
,
=[
+2
×(2.375-2.375)]×
×
,
=[
+2
×0]×
×
,
=
×
×
,
=
;
④10.45÷[(7
-1
)×1.8-0.65÷2
]
=10.45÷[5
×1.8-0.65×
],
=10.45÷[10.75-0.3],
=10.45÷10.45,
=1.
分析:算式①可根據(jù)一個(gè)數(shù)減兩個(gè)數(shù)的和,等于用這個(gè)數(shù)分別減去兩個(gè)數(shù)的減法性質(zhì)計(jì)算;
算式②可根據(jù)乘法分配律計(jì)算;
算式③④根據(jù)四則混合運(yùn)算的運(yùn)算順序計(jì)算即可:先算乘除,再算加減,有括號(hào)的要先算括號(hào)里面的.
點(diǎn)評(píng):當(dāng)算式中同時(shí)含有分?jǐn)?shù)與小數(shù)時(shí),要根據(jù)式中數(shù)據(jù)的特點(diǎn)靈活將它們互化后再進(jìn)行計(jì)算.