分析:算式(1)中可將32拆分為8×4,然后再據(jù)乘法交換律及結(jié)合律進(jìn)行計(jì)算;
算式(2)可根據(jù)一個(gè)數(shù)連續(xù)減去兩個(gè)數(shù),可以用這個(gè)數(shù)減去這兩個(gè)數(shù)的和,使計(jì)算更加簡(jiǎn)便;
算式(3)可根據(jù)加法的交換律和結(jié)合律計(jì)算更加簡(jiǎn)便;
算式(4)可根據(jù)乘法分配律進(jìn)行計(jì)算,使計(jì)算更加簡(jiǎn)便;
算式(5)、(6)根據(jù)四則混合運(yùn)算的運(yùn)算順序計(jì)算即可.
解答:解:(1)2.5×1.25×32,
=2.5×1.25×8×4,
=(2.5×4)×(1.25×8),
=10×10,
=100;
(2)10.36-3.53-6.47,
=10.36-(3.53+6.47),
=10.36-10,
=0.36;
(3)2.1+2
+1.19+3
,
=(2
+3
)+(2.1+1.19),
=6+3.29,
=9.29;
(4)35×(
+),
=35×
+35×
,
=21+10,
=31;
(5)24×[(
-)÷
],
=24×[(
-)×
],
=24×[
×],
=24×
,
=8;
(6)
÷[×(-)],
=
÷[
×
-×],
=
÷[
-],
=
÷[
-],
=
÷,
=
×9,
=2
;
點(diǎn)評(píng):本題考查了運(yùn)算定律,運(yùn)算性質(zhì),四則混合運(yùn)算等內(nèi)容的掌握運(yùn)用情況及靈活運(yùn)用所學(xué)知識(shí)的運(yùn)用情況.