Question

1．靈活計(jì)算．
（$\frac{6}{7}$-$\frac{2}{5}$）÷$\frac{1}{35}$                  
$\frac{7}{8}$×0.375+$\frac{3}{8}$÷$\frac{8}{9}$
$\frac{4}{13}$×$\frac{2}{3}$÷$\frac{4}{13}$×$\frac{2}{3}$                     
99×$\frac{97}{98}$．

Answer 1

分析 ①②先把除法變成乘法，再運(yùn)用乘法分配律簡(jiǎn)算；
③利用只有乘除號(hào)沒(méi)有括號(hào)的情況下，可以先算除法計(jì)算即可；
④把99=98+1，按照乘法分配律展開(kāi)，計(jì)算比較得出答案即可．

解答 解：①（$\frac{6}{7}$-$\frac{2}{5}$）÷$\frac{1}{35}$
=（$\frac{6}{7}$-$\frac{2}{5}$）×35
=$\frac{6}{7}$×35-$\frac{2}{5}$×35
=30-14
=16

$②\frac{7}{8}$×0.375+$\frac{3}{8}$÷$\frac{8}{9}$
=$\frac{7}{8}$×$\frac{3}{8}$+$\frac{3}{8}$×$\frac{9}{8}$
=（$\frac{7}{8}$+$\frac{9}{8}$）×$\frac{3}{8}$
=2×$\frac{3}{8}$
=$\frac{3}{4}$

③$\frac{4}{13}$×$\frac{2}{3}$$÷\frac{4}{13}$×$\frac{2}{3}$
=（$\frac{4}{13}$$÷\frac{4}{13}$）×$\frac{2}{3}$×$\frac{2}{3}$
=1×$\frac{2}{3}$×$\frac{2}{3}$
=$\frac{4}{9}$

④99×$\frac{97}{98}$
=（98+1）×$\frac{97}{98}$
=98×$\frac{97}{98}$+1×$\frac{97}{98}$
=97$+\frac{97}{98}$
=97$\frac{97}{98}$

點(diǎn)評(píng) 完成本題要注意分析式中數(shù)據(jù)，運(yùn)用合適的簡(jiǎn)便方法計(jì)算．