分析:解比例,根據(jù)比例的性質先把比例式轉化成兩外項積等于兩內(nèi)項積的形式,就是已學過的簡易方程,再解簡易方程即可.
解答:解:(1)
=
,
75x=25×1.2,
75x÷75=30÷75,
x=0.4;
(2)25:x=
:4,
x=25×4,
x÷
=100÷
,
x=400;
(3)6.5:x=3.25:4,
3.25x=6.5×4,
3.25x=26,
3.25x÷3.25=26÷3.25,
x=8;
(4)
:
=
:x,
x=
×
,
x÷
=
÷
,
x=
;
(5)0.8:
=x:6,
x=0.8×6,
x
÷=4.8÷
,
x=7.2;
(6)27:x=15:
,
15x=27×
,
15x=15,
x=1;
(7)4:
=
,
x=4×25,
x÷
=100÷
,
x=150;
(8)x:3=0.5:5,
5x=3×0.5,
5x=1.5,
x=0.3;
(9)
:
=x:15,
x=
×15,
x=
,
x÷
=
÷
,
x=40;
(10)
:x=3:12,
3x=
×12,
3x=9,
x=3;
(11)
:
=
:x,
x=
×
,
x÷
=
÷
,
x=
;
(12)
:
=x:15,
x=
×15,
x=
,
x÷
=
÷
,
x=40;
(13)13:7=
,
7x=13×14,
7x÷7=182÷7,
x=26;
(14)6:x=1
:50%,
1.2x=6×50%,
1.2x=3,
x=2.5;
(15)
:
=x:12,
x=
×12,
x=8,
x=48.
點評:此題主要考查比例的基本性質和等式的性質的靈活應用.