(2012?江蘇)解方程.
(1)
1
20
1
6
=
x
6
                           
(2)
0.01x
0.04
-
0.27x-0.18
0.02
=1
分析:(1)根據(jù)比例的性質(zhì)轉(zhuǎn)化為
1
6
×
x
6
=
1
20
,再根據(jù)等式的基本性質(zhì),方程的兩的兩邊同時(shí)除以
1
36
來解,
(2)先化簡方程為0.36-0.53x=0.04,再根據(jù)等式的基本性質(zhì),方程的兩邊同時(shí)加上0.53x,再同時(shí)減去0.04,最后再再除以0.53來解.
解答:解:(1)
1
20
1
6
=
x
6
,
            
1
6
×
x
6
=
1
20

        
1
36
x÷
1
36
=
1
20
÷
1
36
,
                x=
9
5
;

(2)
0.01x
0.04
-
0.27x-0.18
0.02
=1

                  0.36-0.53x=0.04,
            0.36-0.53x+0.53x=0.04+0.53x,
                        0.36=0.04+0.53x,
                   0.36-0.04=0.04+0.53x-0.04,
                        0.32=0.53x,
                  0.32÷0.53=0.53x÷0.53,
                           x=
32
53
點(diǎn)評(píng):此題考查利用等式的性質(zhì)和比例的基本性質(zhì)解方程,注意等號(hào)對(duì)齊.
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