(1)
1
2
+
1
5
=
(2)12×(
1
4
+
1
6
)=
(3)
3
20
×
(6
2
3
×
0.8+6
2
3
×
 0.2)=
(4)(
1
15
+
2
17
)×15×17=
(5)
1
1×2
+
1
2×3
+
1
3×4
+…+
1
98×99
+
1
99×100
分析:(1)先通分,再計算;
(2)根據(jù)乘法分配律進行計算;
(3)根據(jù)乘法分配律進行計算;
(4)根據(jù)乘法分配律進行計算;
(5)根據(jù)分數(shù)的拆項進行計算.
解答:解:
(1)
1
2
+
1
5

=
5
10
+
2
10
,
=
7
10


(2)12×(
1
4
+
1
6
),
=12×
1
4
+12×
1
6
,
=3+2,
=5;

(3)
3
20
×
(6
2
3
×
0.8+6
2
3
×
 0.2),
=
3
20
×
[6
2
3
×
(0.8+0.2)],
=
3
20
×
[6
2
3
×
1],
=
3
20
×
6
2
3
,
=1;

(4)(
1
15
+
2
17
)×15×17,
=
1
15
×15×17+
2
17
×15×17,
=17+30,
=47;

(5)
1
1×2
+
1
2×3
+
1
3×4
+…+
1
98×99
+
1
99×100
,
=(1-
1
2
)+(
1
2
-
1
3
)+(
1
3
-
1
4
)+…+(
1
98
-
1
99
)+(
1
99
-
1
100
),
=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+…+
1
98
-
1
99
+
1
99
-
1
100
,
=1-
1
100

=
99
100
點評:四則運算,先弄清運算順序,然后再進一步計算,能簡算的要簡算.
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