Question

互質(zhì)數(shù)一定是由質(zhì)數(shù)和質(zhì)數(shù)合成的．

錯(cuò)誤

．

Answer 1

分析：自然數(shù)中，有公因數(shù)1的兩個(gè)數(shù)為互質(zhì)數(shù)．由此可知，只要只有公因數(shù)1，這兩個(gè)數(shù)就為互質(zhì)數(shù)，和這兩個(gè)數(shù)是否為質(zhì)數(shù)無(wú)關(guān)，如8與9互質(zhì)，兩個(gè)數(shù)都為合數(shù)，7與9互質(zhì)，一個(gè)質(zhì)數(shù)一個(gè)合數(shù)．所以互質(zhì)數(shù)一定是由質(zhì)數(shù)和質(zhì)數(shù)合成的是錯(cuò)誤的．

解答：解：根據(jù)互質(zhì)數(shù)的意義可知，
只要只有公因數(shù)1，這兩個(gè)數(shù)就為互質(zhì)數(shù)，和這兩個(gè)數(shù)是否為質(zhì)數(shù)無(wú)關(guān)．
所以互質(zhì)數(shù)一定是由質(zhì)數(shù)和質(zhì)數(shù)合成的說(shuō)法錯(cuò)誤．
故答案為：錯(cuò)誤．

點(diǎn)評(píng)：質(zhì)數(shù)根據(jù)自然數(shù)個(gè)體含有因數(shù)的個(gè)數(shù)進(jìn)行定義的，互質(zhì)數(shù)是根據(jù)兩個(gè)自然數(shù)共有因數(shù)的個(gè)數(shù)定義的．