考點:奇數(shù)與偶數(shù)的初步認識,合數(shù)與質(zhì)數(shù)
專題:數(shù)的整除
分析:根據(jù)找一個數(shù)因數(shù)的方法,先找出24所有的因數(shù),進而根據(jù)奇數(shù)、合數(shù)、質(zhì)數(shù)和偶數(shù)的意義分類得解.
解答:
解:24所有的因數(shù)有:1,2,3,4,6,8,12,24
在這些因數(shù)中:
奇數(shù)有:1,3
合數(shù)有:4,6,8,12,24
質(zhì)數(shù)有:2,3
偶數(shù)有:2,4,6,8,12,24.
故答案為:1,2,3,4,6,8,12,24;1,3;4,6,8,12,24;2,3;2,4,6,8,12,24.
點評:解決此題要明確奇數(shù)、合數(shù)、質(zhì)數(shù)和偶數(shù)的意義,要熟記在心,不能混淆.