分析:法一,根據(jù)求反函數(shù)的步驟進(jìn)行轉(zhuǎn)換,即可求出原函數(shù)的反函數(shù).要求函數(shù)的反函數(shù)的步驟一般為:①反表示②將x,y互換③寫出函數(shù)的定義域.
法二,我們也可以根據(jù)互為反函數(shù)的兩個(gè)函數(shù)圖象關(guān)于直線y=x對(duì)稱,即(a,b)點(diǎn)與(b,a)點(diǎn)分別在原函數(shù)和反函數(shù)圖象上,利用特值排除法解題.
解答:解:法一:由y=log
2則
=2
y則x=
∴函數(shù)y=log
2(x>1)的反函數(shù)是y=
(x<0)
法二:∵原函數(shù)和反函數(shù)的圖象關(guān)于直線y=x對(duì)稱,
∴(a,b )點(diǎn)在原函數(shù)圖象上,則(b,a )點(diǎn)在反函數(shù)圖象上
∵(2,-1)點(diǎn)在原函數(shù)圖象上,則(-1,2)點(diǎn)在反函數(shù)圖象上
代入驗(yàn)證發(fā)現(xiàn)y=
(x<0)符合要求
故選B
點(diǎn)評(píng):在解答求反函數(shù)的解析式的選擇題時(shí),我們一般有兩種方法:一是根據(jù)求反函數(shù)的常規(guī)步驟:①反表示②將x,y互換③寫出函數(shù)的定義域.二是根據(jù)原函數(shù)和反函數(shù)的圖象關(guān)于直線y=x對(duì)稱,即(a,b )點(diǎn)在原函數(shù)圖象上,則(b,a )點(diǎn)在反函數(shù)圖象上,在函數(shù)上尋找一個(gè)易于計(jì)算的特殊值點(diǎn),代入用排除法求解.