(本題滿分15分)

設(shè)函數(shù).

(Ⅰ)當(dāng)時(shí),解不等式:;

(Ⅱ)求函數(shù)的最小值;

(Ⅲ)求函數(shù)的單調(diào)遞增區(qū)間.

 

【答案】

【解析】解:(Ⅰ)…………3分

(Ⅱ)令

(1)當(dāng)時(shí),上單調(diào)遞增,故

(2)當(dāng)時(shí),可證上單調(diào)遞增,故

(3)當(dāng)時(shí),

綜合得,當(dāng)時(shí),;當(dāng)時(shí),…………9分

(Ⅲ),令,可得

當(dāng)時(shí),單調(diào)遞增區(qū)間為

當(dāng)時(shí),由

(2)當(dāng)時(shí),單調(diào)遞增區(qū)間為

(3)當(dāng)時(shí),單調(diào)遞增區(qū)間為…………15分

 

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