=2+3+4+--+ n. =1+2+3+4+--+ n =.Tn= 查看更多

 

題目列表(包括答案和解析)

已知f(x)=
4+
1
x2
,數(shù)列{an}的前n項(xiàng)和為Sn,點(diǎn)Pn(an
1
an+1
)(n∈N*)在曲線y=f(x)上,且a1=1,an>0.
(1)求數(shù)列{an}的通項(xiàng)公式an;
(2)數(shù)列{bn}的首項(xiàng)b1=1,前n項(xiàng)和為Tn,且
Tn+1
an2
=
Tn
an+12
+16n2-8n-3
,求數(shù)列{bn}的通項(xiàng)公式bn

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在數(shù)列{an}(n∈N*)中,a1=1,前n項(xiàng)和Sn滿足nSn+1-(n+3)Sn=0.
(1)求{an}的通項(xiàng)公式;
(2)若bn=4(
an
n
)2
,求數(shù)列{(-1)nbn}的前n項(xiàng)和Tn
(3)求證:
1+a1
a1
1+a2
a2
•…•
1+an
an
<9

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已知數(shù)列,其前n項(xiàng)和Sn滿足是大于0的

常數(shù)),且a1=1,a3=4.

(1)求的值;

(2)求數(shù)列的通項(xiàng)公式an;w.w.w.k.s.5.u.c.o.m          

(3)設(shè)數(shù)列的前n項(xiàng)和為Tn,試比較與Sn的大小.

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已知f(x)=
4+
1
x2
,數(shù)列{an}的前n項(xiàng)和為Sn,點(diǎn)Pn(an,
1
an+1
)(n∈N*)在曲線y=f(x)上,且a1=1,an>0.
(1)求數(shù)列{an}的通項(xiàng)公式an;
(2)數(shù)列{bn}的首項(xiàng)b1=1,前n項(xiàng)和為Tn,且
Tn+1
an2
=
Tn
an+12
+16n2-8n-3
,求數(shù)列{bn}的通項(xiàng)公式bn

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等比數(shù)列124,…的前2n項(xiàng)的和為S2n,等比數(shù)列1,3,9,…的前n項(xiàng)和為Tn,則( )

  AS2nTn           BS2nTn

  CS2n =Tn           DS2nTn

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