0.13+0.23+0.33+…+0.93
分析:從1開始的連續(xù)自然數(shù)的立方和公式為:13+23+33+43+…+n3=(1+2+3+4+…+n)2,據(jù)此利用公式計算比較簡便.
解答:解:0.13+0.23+0.33+…+0.93,
=(1+2+3+…+9)2×
1
1000
,
=2025×
1
1000

=2.025.
點評:熟記從1開始連續(xù)自然數(shù)的立方和公式是解決此題的關(guān)鍵.
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(3)
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2
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11
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4
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科目:小學(xué)數(shù)學(xué) 來源: 題型:

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180÷60=12×25=0÷90=
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0.36+0.64=64.32÷16=72.8÷0.8=
8.4×0.2+1.6×0.2=8.4÷4.2=0.05×0.8=
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12÷0.3=2.87÷0.7=13÷4=
24÷4+56÷4=2.1×0.3÷2.1=2.3-0÷8.1=
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