1×1+2×2+3×3+…+2012×2012+2013×2013的個(gè)位數(shù)字是
9
9
分析:1×1+2×2+3×3+…+2012×2012+2013×2013的個(gè)位數(shù)字是1,4,9,6,5,6,9,4,1,0,共10個(gè)一個(gè)循環(huán),先求出它們的和,再找到組數(shù),相加即可求解.
解答:解:1×1+2×2+3×3+…+2012×2012+2013×2013的個(gè)位數(shù)字是1,4,9,6,5,6,9,4,1,0,共10個(gè)一個(gè)循環(huán),
1+4+9+6+5+6+9+4+1+0=45,
因?yàn)?013÷10=201…3,
所以個(gè)位數(shù)字是5+1+4+9=9.
答:1×1+2×2+3×3+…+2012×2012+2013×2013的個(gè)位數(shù)字是9.
故答案為:9.
點(diǎn)評(píng):考查了乘方和乘積的個(gè)位數(shù),解答此題需從平方考慮,順次進(jìn)行,發(fā)現(xiàn)規(guī)律,解決問題.
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