1×1+2×2+3×3+…1997×1997+1998×1998的個位數(shù)字是
9
9
分析:由于1~10這十個數(shù)的平方的個位數(shù)分別為1,4,9,6,5,6,9,4,1,0.以后連續(xù)自然數(shù)平方的個位數(shù)就按這個個數(shù)進行循環(huán)的.因此我們可將這十個數(shù)當成一個整體,它們的和的個位數(shù)為5.然后根據(jù)最后一個數(shù)1998進行分析計算即可.
解答:解:由于1~10這十個數(shù)的平方的個位數(shù)分別為1,4,9,6,5,6,9,4,1,0.
因此我們可將這十個數(shù)當成一個整體,它們的和為:
1+4+9+6+5+6+9+4+1+0=45,
即它們和的個位數(shù)為5.
1998÷10=199…8,
則1×1+2×2+3×3+…1997×1997+1998×1998的個位數(shù)字和是:
199×5+(1+4+9+6+5+6+9+4)
=995+44,
=1039.
即最終的個位為9.
故答案為:9.
點評:通過試算,計算出連續(xù)自然數(shù)平方個位數(shù)的排列規(guī)律,并由此進行分析是完成本題的關鍵.
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