[1-(3.1-3.09)]÷(0.8+
1315
).
分析:先算小括號內(nèi)的,原式變?yōu)閇1-0.01]÷(
4
5
+
13
15
),即[1-0.01]÷
5
3
,把除法變?yōu)槌朔ǎ碵1-0.01]×0.6,然后運用乘法分配律簡算即可.
解答:解:[1-(3.1-3.09)]÷(0.8+
13
15
),
=[1-0.01]÷(
4
5
+
13
15
),
=[1-0.01]÷
5
3
,
=[1-0.01]×
3
5
,
=[1-0.01]×0.6,
=0.6-0.01×0.6,
=0.6-0.006,
=0.594.
點評:完成此題,應注意數(shù)字轉化,運用所學知識,靈活簡算.
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