(1.23+4.25+7.27)÷3+16÷(2÷1.25)
分析:先運算兩個小括號里面的加法和除法,再算括號外的兩個除法,最后算括號外的加法.
解答:解:(1.23+4.25+7.27)÷3+16÷(2÷1.25),
=(5.48+7.27)÷3+16÷(2÷1.25),
=12.75÷3+16÷1.6,
=4.25+10,
=14.25.
點評:本題考查了小數(shù)的四則混合運算,關(guān)鍵是理清楚運算的順序,然后根據(jù)運算順序逐步求解即可.
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