Question

用質(zhì)量分?jǐn)?shù)為95%的濃硫酸和質(zhì)量分?jǐn)?shù)為5%的稀硫酸配制成質(zhì)量分?jǐn)?shù)為30%的硫酸溶液2000g，問需這兩種溶液各多少g？

Answer 1

考點(diǎn)：有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的簡單計算

專題：溶液的組成及溶質(zhì)質(zhì)量分?jǐn)?shù)的計算

分析：根據(jù)溶液混合前后，溶質(zhì)的質(zhì)量不變，結(jié)合溶質(zhì)質(zhì)量=溶液質(zhì)量×溶質(zhì)的質(zhì)量分?jǐn)?shù)，進(jìn)行分析解答．

解答：解：用質(zhì)量分?jǐn)?shù)為95%的濃硫酸和質(zhì)量分?jǐn)?shù)為5%的稀硫酸配制成質(zhì)量分?jǐn)?shù)為30%的硫酸溶液2000g，設(shè)需要質(zhì)量分?jǐn)?shù)為95%的濃硫酸的質(zhì)量為x，
則95%x+（2000g-x）×5%=2000g×30%    x≈555.6g   
需要質(zhì)量分?jǐn)?shù)為5%的稀硫酸的質(zhì)量為2000g-555.6g=1444.4g．
答：需質(zhì)量分?jǐn)?shù)為95%的濃硫酸和質(zhì)量分?jǐn)?shù)為5%的稀硫酸的質(zhì)量分別是555.6g、1444.6g．

點(diǎn)評：本題難度不大，掌握溶液混合前后溶質(zhì)的質(zhì)量不變、溶質(zhì)質(zhì)量=溶液質(zhì)量×溶質(zhì)的質(zhì)量分?jǐn)?shù)是正確解答本題的關(guān)鍵．