Question

若|3x+2y﹣4|+27（5x+6y）²=0，則x，y的值分別是（　�。�                         

A．                 B．                 C．                   D．

Answer 1

B

【考點(diǎn)】解二元一次方程組；非負(fù)數(shù)的性質(zhì)：絕對(duì)值；非負(fù)數(shù)的性質(zhì)：偶次方．                 

【專題】計(jì)算題；一次方程（組）及應(yīng)用．                                             

【分析】利用非負(fù)數(shù)的性質(zhì)列出方程組，求出方程組的解得到x與y的值即可．                 

【解答】解：∵|3x+2y﹣4|+27（5x+6y）²=0，                                         

∴，                                                                              

①×3﹣②得：4x=12，即x=3，                                                                

把x=3代入①得：y=﹣，                                                                      

則方程組的解為，                                                                      

故選B                                                                                                

【點(diǎn)評(píng)】此題考查了解二元一次方程組，以及非負(fù)數(shù)的性質(zhì)，熟練掌握運(yùn)算法則是解本題的關(guān)鍵．