考點(diǎn):有理數(shù)的混合運(yùn)算
專題:
分析:①根據(jù)同號(hào)兩數(shù)相加,即可得出答案;
②根據(jù)異號(hào)兩數(shù)相加,即可得出答案;
③先將減法變成加法再進(jìn)行計(jì)算;
④先將減法變成加法,再根據(jù)0加任何數(shù)仍得這個(gè)數(shù)進(jìn)行計(jì)算;
⑤根據(jù)同號(hào)兩數(shù)相乘的法則,即可得出答案;
⑥根據(jù)異號(hào)兩數(shù)相乘的法則,即可得出答案;
⑦根據(jù)同號(hào)兩數(shù)相除的法則,即可得出答案;
⑧三個(gè)數(shù)相乘,先判斷符號(hào),再把它們的絕對(duì)值相乘.
解答:解:①原式=-(12+6)
=-18;
②原式=-(8-5)
=-3;
③原式=(-3)+(-6)
=-(3+6)
=-9;
④原式=0+(-7)
=-7;
⑤原式=4×5
=20;
⑥原式=-6×2
=-12;
⑦原式=
×
=
;
⑧原式=1×1×
=
;
故答案為-18,-3,-9,-7,20,-12,
,
.
點(diǎn)評(píng):本題考查了有理數(shù)的混合運(yùn)算,注意:“--得+,-+得-,++得+,+-得-”的法則.