Question

若將6g食鹽溶解于94克水中
（1）求該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)
（2）若向其中加入10g水則該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為多少．

Answer 1

考點(diǎn)：有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的簡單計(jì)算

專題：溶液的組成及溶質(zhì)質(zhì)量分?jǐn)?shù)的計(jì)算

分析：（1）根據(jù)溶質(zhì)質(zhì)量分?jǐn)?shù)=

溶質(zhì)質(zhì)量

溶液質(zhì)量

×100%，進(jìn)行分析解答．
（2）根據(jù)加水前后，溶質(zhì)的質(zhì)量不變，進(jìn)行分析解答．

解答：解：（1）該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為

6g

6g+94g

×100%=6%．
（2）若向其中加入10g水，則該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為

6g

6g+94g+10g

×100%≈5.5%．
故答案為：（1）該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為6%；（2）向其中加入10g水則該溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)為5.5%

點(diǎn)評：本題難度不大，掌握溶質(zhì)質(zhì)量分?jǐn)?shù)=

溶質(zhì)質(zhì)量

溶液質(zhì)量

×100%并能靈活運(yùn)用是正確解答本題的關(guān)鍵．